Champa went to a 'Sale' to purchase some pant | vedclass

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Question

(A) Let us denote the number of pants by $x$ and the number of skirts by $y$. According to the problem,the equations formed are:$y = 2x - 2$ $...(1)$$

Vedclass · Accepted Answer

$1$ pant,$0$ skirts

Vedclass · Answer

(A) Let us denote the number of pants by $x$ and the number of skirts by $y$. According to the problem,the equations formed are:$y = 2x - 2$ $...(1)$$y = 4x - 4$ $...(2)$To solve this pair of linear equations graphically,we find two solutions for each equation:For equation $(1)$,$y = 2x - 2$:$x$$2$$0$$y$$2$$-2$For equation $(2)$,$y = 4x - 4$:$x$$0$$1$$y$$-4$$0$Plotting these points on a graph and drawing the lines,we find that the two lines intersect at the point $(1, 0)$. Thus,the solution is $x = 1$ and $y = 0$. Therefore,Champa purchased $1$ pant and $0$ skirts.

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